給SQL Server傳送數組參數的變通辦法
來源：程序員人生 發布時間：2014-03-01 07:42:09 閱讀次數：2817次
最近一直在做Dnn模塊的開發,過程中碰到這么一個問題,需要同時插入N條數據,不想在程序里控制,但是SQL Sever又不支持數組參數.所以只能用變通的辦法了.利用SQL Server強大的字符串處理傳把數組格式化為類似"1,2,3,4,5,6"。然后在存儲過程中用SubString配合CharIndex把分割開來.
詳細的存儲過程
| 以下為引用的內容： CREATE PROCEDURE dbo.ProductListUpdateSpecialList
@ProductId_Array varChar(800),
@ModuleId int
AS
DECLARE @PointerPrev int
DECLARE @PointerCurr int
DECLARE @TId int
Set @PointerPrev=1
set @PointerCurr=1 begin transaction
Set NoCount ON
delete from ProductListSpecial where ModuleId=@ModuleId Set @PointerCurr=CharIndex(',',@ProductId_Array,@PointerPrev+1)
set @TId=cast(SUBSTRING(@ProductId_Array,@PointerPrev,@PointerCurr-@PointerPrev) as int)
Insert into ProductListSpecial (ModuleId,ProductId) Values(@ModuleId,@TId)
SET @PointerPrev = @PointerCurr
while (@PointerPrev+1 < LEN(@ProductId_Array))
Begin
Set @PointerCurr=CharIndex(',',@ProductId_Array,@PointerPrev+1)
if(@PointerCurr> 0)
Begin
set @TId=cast(SUBSTRING(@ProductId_Array,@PointerPrev+1,@PointerCurr-@PointerPrev-1) as int)
Insert into ProductListSpecial (ModuleId,ProductId) Values(@ModuleId,@TId)
SET @PointerPrev = @PointerCurr
End
else
Break
End set @TId=cast(SUBSTRING(@ProductId_Array,@PointerPrev+1,LEN(@ProductId_Array)-@PointerPrev) as int)
Insert into ProductListSpecial (ModuleId,ProductId) Values(@ModuleId,@TId)
Set NoCount OFF
if error=0
begin
commit transaction
end
else
begin
rollback transaction
end
GO |
網友Bizlogic對此的改進方法:
應該用SQL2000 OpenXML更簡單，效率更高，代碼更可讀：
| 以下為引用的內容： CREATE Procedure [dbo].[ProductListUpdateSpecialList]
(
@ProductId_Array NVARCHAR(2000),
@ModuleId INT
) AS delete from ProductListSpecial where ModuleId=@ModuleId -- If empty, return
IF (@ProductId_Array IS NULL OR LEN(LTRIM(RTRIM(@ProductId_Array))) = 0)
RETURN DECLARE @idoc int EXEC sp_XML_preparedocument @idoc OUTPUT, @ProductId_Array Insert into ProductListSpecial (ModuleId,ProductId)
Select
@ModuleId,C.[ProductId]
FROM
OPENXML(@idoc, '/Products/Product', 3)
with (ProductId int ) as C
where
C.[ProductId] is not null EXEC sp_XML_removedocument @idoc |
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