PHP獲得跳轉的真實地址實例
來源：程序員人生 發布時間：2014-05-23 21:07:03 閱讀次數：3310次
現在有很多的短網址應用,點擊就跳轉到縮短之前的網址了,那今天我們就來看一下,PHP如何獲取短網址跳轉之前的網址,其實也很簡單,就是用php的get_headers 函數,取得Response Headers,之后慢慢分析就行了。
給出具體實現方法,代碼如下:
- $header = get_headers($url, 1);
- if (strpos($header[0], ’301′) || strpos($header[0], ’302′)) {
- if (is_array($header['Location'])) {
- return $header['Location'][count($header['Location'])-1];
- } else {
- return $header['Location'];
- }
- } else {
- return $url;
- }
實例二,代碼如下:
-
- echo get_redirect_url('http://www.phpfensi.com');
-
- function get_redirect_url($url){
- $redirect_url = null;
- $url_parts = @parse_url($url);
- if (!$url_parts) return false;
- if (!isset($url_parts['host'])) return false;
- if (!isset($url_parts['path'])) $url_parts['path'] = '/';
- $sock = fsockopen($url_parts['host'], (isset($url_parts['port']) ? (int)$url_parts['port'] : 80), $errno, $errstr, 30);
- if (!$sock) return false;
- $request = "HEAD " . $url_parts['path'] . (isset($url_parts['query']) ? '?'.$url_parts['query'] : '') . " HTTP/1.1rn";
- $request .= 'Host: ' . $url_parts['host'] . "rn";
- $request .= "Connection: Closernrn";
- fwrite($sock, $request);
- $response = '';
- while(!feof($sock)) $response .= fread($sock, 8192);
- fclose($sock);
- if (preg_match('/^Location: (.+?)$/m', $response, $matches)){
- if ( substr($matches[1], 0, 1) == "/" )
- return $url_parts['scheme'] . "://" . $url_parts['host'] . trim($matches[1]);
- else
- return trim($matches[1]);
- } else {
- return false;
- }
- }
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