A string is called a k-string if it can be represented as k concatenated copies of some string. For example, the string "aabaabaabaab" is at the same time a 1-string, a 2-string and a 4-string, but it is not a 3-string, a 5-string, or a 6-string and so on. Obviously any string is a 1-string.
You are given a string s, consisting of lowercase English letters and a positive integer k. Your task is to reorder the letters in the string sin such a way that the resulting string is a k-string.
The first input line contains integer k (1?≤?k?≤?1000). The second line contains s, all characters in s are lowercase English letters. The string length s satisfies the inequality 1?≤?|s|?≤?1000, where |s| is the length of string s.
Rearrange the letters in string s in such a way that the result is a k-string. Print the result on a single output line. If there are multiple solutions, print any of them.
If the solution doesn't exist, print "⑴" (without quotes).
解題思路：給1個(gè)串，問是不是能由k個(gè)相同的串聯(lián)接而成。
用STL里的map。掃1遍，分別記錄每一個(gè)字符的個(gè)數(shù)，在判斷所有的字符是不是是k的倍數(shù)，若不是，則輸出⑴；否則，遍歷順次map，每一個(gè)字符輸出（總個(gè)數(shù)）/k個(gè)，然后重復(fù)k次便可。
AC代碼：
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